Hancock had 36 votes for Ron Paul in 2008: http://www.boston.com/news/politics/2008/nh/nh_primary_gop_results_by_town/
Here's another interesting result:
Keene, NH:
Romney: 33%
Hunstman: 23%
Paul: 22%
Really Keene? C'mon "free-staters" wtf?
Anyway, does anyone know if there's a breakdown by town for '08? Might be useful to compare Hancock '08 if that's available.
Hancock had 36 votes for Ron Paul in 2008: http://www.boston.com/news/politics/2008/nh/nh_primary_gop_results_by_town/
Hancock had 36 votes for Ron Paul in 2008: http://www.boston.com/news/politics/2008/nh/nh_primary_gop_results_by_town/
Not many free staters in numbers. Even amongst them I imagine there are a lot of anarchists who are philosophically opposed to voting and/or stubborn enough to have voted for Gary.
So we're supposed to believe that in 2008, when Ron Paul only got 7% of the vote in NH, he got 36 votes in Hancock (a place named after a founding father, anarchist and revolutionary) but in 2012, when Ron Paul garnered over 23% of the total vote in NH, he gets 0 votes in Hancock?
THIS IS OBVIOUS FRAUD and needs to be investigated.
Hancock had 36 votes for Ron Paul in 2008: http://www.boston.com/news/politics/2008/nh/nh_primary_gop_results_by_town/
Sometimes I hate anarchists. I thought the point of picking NH for the FSP was partially because of it being the first primary, therefore state politics are very influential on national politics.
Libertarians are just as bad.
There's 25,000 of them registered in Iowa.
You would think if you go through the effort to join a party that isn't mainstream, you would make an effort to vote in the most important election in the nation?
Geeze...that woulda blown away Iowa...