Wyoming caucus results - 8% reporting

Well, we will at least have one vote by Diana and I think I saw another person on these forums from Wyoming...so that makes 2 votes for Ron Paul out of the 12 people who live in Wyoming.

I hope a few of the other 10 support Ron Paul too. I wonder if Diana and the other guy were hogging the only computer in the state to check Ron Paul forums.

LOL I've been chuckling for five mins after reading this
 
What does it mean when a delegate is undeclared under the wyoming system?

Under any state's system, the delegates to the national convention in September vote for the presidential candidate on the first ballot
according to the state rules - usually decided by the citizens that vote in the primary one way or another.

Everyone is "uncommitted" on the second and any subsequent ballots if no one candidate has the majority needed on the first round.

It sounds like Wyoming can have some delegates that can be uncommitted - at least on paper and depending on who the delegate secretly wants - from the getgo.

Good luck Diana !
 
Even 1 Delegate is great for us.

Goshen & Fremont both started at 8am Central? So 10am Est? They should be reporting ASAP.
 
So we have now Romney 5 and Hunter 1.

Looks like Wyoming is the perfect state for Romney.


So now everyone wins the states which are made for them.

Iowa for Huckabee and Wyoming for Romney.


And the rest is for Ron Paul. Should be enough to win. :D
 
The excel file says 5 Romney (4 delegate,1alternate), 1 Hunter, 1 undecided
 
Update:

Romney 7 (4 Del, 3 Alt)
Hunter 2 (1 Del, 1 Alt)
Thompson 2 (1 Del, 1 Alt)
McCain 1 (Alt)
Undeclared 1 (Alt)
 
Last edited:
Update:

Romney 7
Hunter 2
Thompson 2
McCain 1
Undeclared 1

you're not discriminating between delegates and alternates. The correct count for delegates is:

Romney: 4
Hunter: 1
Thompson: 1

For Alternates:

Romney: 3
Hunter: 1
Thompson: 1
McCain: 1
 
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