When that happens over and over and over and over again, it starts to look like fraud. And when all of the incompetence and errors seem to move in the same direction, it also starts to look like fraud. Of course, if you are the person responsible for such things, you say it's "error."
Well, I was one of the first people here to analyze the data that came out last week. I caught the Waldo error, the Waterville error, and posted about them here last Sunday night. So, I'm not one to say "oh, everything's fine" I caught missing data, erroneous totals, saw strange boosts in turnout, etc.
But, from what I can tell, they fixed the errors.
There might be fraud. I have no idea. But what I'd like to see is some actual, real allegations of something. Not crazy math.
It's easy to get the real count.
Start with the most recent data from the Maine GOP. They have fixed most of the errors, if not 100%.
Question 1 - do you have any problems at all with the Maine GOP data? If so, what exactly should be changed or modified? Yes, the totals are still screwed up.
But we only care about Paul and Romney at this point. Are Pauls totals right? Are Romney's totals right? If no, what town needs corrected?
I would argue that New Portland (and perhaps other towns in Somerset County) fall under this category. Apparently, one of the higherups in Somerset County wouldn't could the votes unless the town had the town clerk there.
But, we have a number from the Maine GOP, Paul down by 239.
Then, just add the results of the caucuses.
Rome, Clinton in Kennebec
2 supercaucuses in Hancock
The Washington County caucus and the Danforth Caucus.
And then you have your number.
There isn't any mystery.
If you have specific allegations of fraud in any particular case, make them.
By the way, the data for the Danforth Caucus - not included in some Washington County totals, is
Romney 6
Paul 4
Santorum 2
Gingrich 1.
If the Wash Co totals you're using have Ron Paul 167, they include the Danforth. If the Wash Co totals you're using have Ron Paul 163, you have totals without Danforth.