DirectDemocracy
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Giuliani gets 9.11% in 3 districts=9/11=sick joke?
- Thread starter DirectDemocracy
- Start date
kimosabi
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If anyone thinks there is no f^ckin conspiracy, they are f^ckin idiots who've had too many of their mercury vaccinations, have drunk too much of their floridated water and have watched too much of their sh1tty mind control TV...
This is just as insulting to all of America and those who died on 9/11 as them doing their "Eye of Providence" during one of the 9/11 Memorial's ==> http://au.youtube.com/watch?v=70mZsW1yd5E
Go back to sleep America, the government loves you...
KingTheoden
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You have no idea what you are talking about. The statistical incidence of this is unbelievably high. We are talking number of grains of sand.
Actually, the probability of getting multiple 9.11% votes was incredibly reasonable.
No we're not.
Read the other thread on this. I'm a math major. I know statistics. The statistics of this WOULD have been high if he actually got 9.11%, but he didn't. He got 9.105%, 9.103%, and 9.113%.
Or 9%, 9%, 9%.
depending on what website you read.
wildflower
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Where is the statistics guy who was posting last night?
We should ask him to figure out the statistical probability of this.
Just out of curiousity.
We should ask him to figure out the statistical probability of this.
Just out of curiousity.
Nahh thats not too odd.. there are stranger things out there, I posted this in another forum.
Go look at the results from Hampton county.
McCain - 1,217 - 39%
Romney - 1,217 - 39%
Giuliani - 286 - 9%
Huckabee - 217 - 7%
Paul - 144 - 4%
217 217 217.. ok thats strange.. what about the democrats from the same city?
Clinton - 1,700 - 43%
Obama - 1,295 - 33%
Edwards - 750 - 19%
Richardson - 150 - 4%
Kucinich - 25 - 1%
All divisible by 5.. ok.. somebody mentioned that when people lie with numbers they often repeat them or make them end similarly... Its like a mental version of body language..
Also..
Londonderry has 1221 votes listed as 'write-ins'. Thats about 500% normal. (guessing)
607 on the Republican ballots and 614 on the Democratic.
Go look at the results from Hampton county.
McCain - 1,217 - 39%
Romney - 1,217 - 39%
Giuliani - 286 - 9%
Huckabee - 217 - 7%
Paul - 144 - 4%
217 217 217.. ok thats strange.. what about the democrats from the same city?
Clinton - 1,700 - 43%
Obama - 1,295 - 33%
Edwards - 750 - 19%
Richardson - 150 - 4%
Kucinich - 25 - 1%
All divisible by 5.. ok.. somebody mentioned that when people lie with numbers they often repeat them or make them end similarly... Its like a mental version of body language..
Also..
Londonderry has 1221 votes listed as 'write-ins'. Thats about 500% normal. (guessing)
607 on the Republican ballots and 614 on the Democratic.
This has been posted already.
If the Ghoul's possible range of vote percentages was somewhere between, say, 5% and 15% (I used other numbers earlier...) then there are precisely 1001 different two decimal place results that could occur for his results (Do NOT forget to count 5.00% even, as others have done, although it won't effect the outcome much)... Therefore, for each given county, there is a 1 in 1001 chance that RG will get 9.11% (rounded to the nearest bp, or basis point). That is a 0.1% chance that in any given county, 9.11% will be the result, IF THE ELECTIONS were RANDOM between the given restraints. However, they are NOT random, as we know, because RG ended up with 8.something % of the votes, so there is a distribution centered somewhere around 8.5%. 9.11% would fall in the large portion of the bell curve, increasing the odds from there. Then, take into consideration that there were 300 precincts reporting, and you have a very HIGH likelihood that 9.11% will show up a few times.
If the Ghoul's possible range of vote percentages was somewhere between, say, 5% and 15% (I used other numbers earlier...) then there are precisely 1001 different two decimal place results that could occur for his results (Do NOT forget to count 5.00% even, as others have done, although it won't effect the outcome much)... Therefore, for each given county, there is a 1 in 1001 chance that RG will get 9.11% (rounded to the nearest bp, or basis point). That is a 0.1% chance that in any given county, 9.11% will be the result, IF THE ELECTIONS were RANDOM between the given restraints. However, they are NOT random, as we know, because RG ended up with 8.something % of the votes, so there is a distribution centered somewhere around 8.5%. 9.11% would fall in the large portion of the bell curve, increasing the odds from there. Then, take into consideration that there were 300 precincts reporting, and you have a very HIGH likelihood that 9.11% will show up a few times.
It's not something that can be calculated like you think. Most people think that the odds of getting exactly 9.11% are 1 in 1000.
Except, Ghoul didn't get exactly 9.11%. He got votes that divided into dividends that resulted in 9.11% when rounded to two digits.
Also, these are independant events. That means that, in a given situtation, the statstical result of one does not have an influence on the statistical result of another. So the odds of any of the three happening are the same as the odds of one of the three happening. For example, it enters into the birthday paradox. Did you know that if you got a group of 23 people together, and asked them all their birthdate, the odds are 1:2 that two people share the same date? If you have over 47, the odds jump to almost 99% certainty that two people share the same birthdate. Month and day.
That's what is going on here. An advanced Birthday paradox.
wildflower
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If you think voter fraud doesn't happen, you guys are either naive or trolls.
I posted showing how this is statistically possible.
http://www.ronpaulforums.com/showpost.php?p=899414&postcount=38
Stop with these posts already!
http://www.ronpaulforums.com/showpost.php?p=899414&postcount=38
Stop with these posts already!
KingTheoden
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Absolutely. Diebold's engineers were laughing all night.
KingTheoden
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Votes are usually rounded to the singles or hundredths digit so yeah, he did get 9.11 three times.
If people would for a moment consider that the electronic machines are a colossal joke, the programmers could feed in whatever they want to the machines.
You are correct that each event is independent (sort of, if we simply it to some workable problem) and would have its odds dependent on only the variables present in each town. Of course it was more likely for Rudy to get 9.11 somewhere than Romney for example because the former was predicted to get many more votes.
We could dumb down the problem to a very simple (and less accurate) one by figuring the odds of the numbers coming up randomly:
10 x 10 x 10 = 1 000
However, this greatly overstates the odds because we are interested in a particular number coming up in position a AND a different number repeated in positions b and c.
It should also be noted that we are technically, using this method, required to take into account all numbers 0-100.
I have to crack out my Stats book but will do out the odds using this method. Again, they are going to be way too small because it was obviously more likely that he would get a 9 in position a than a 20 or a 2.
The key is to assigning probability values to each number in each position. That is where significant judgment will come in and it will be very hard for anyone to claim they are especially accurate.
Remember also, we are talking about this all happening for a given candidate and a candidate who has special significance for the number 911.
Bottom line: The odds are next to impossible.
