there is already schiff, kokesh and others. If you are saying not run, its his decision, but i want him to run to have america hear his message one more time and know exactly what they didn't vote for the first time.
then in the future, no matter what, america will have to live with the consequences of its choice in 2012.
He has no interest in that, trust me.I would like to see Thomas E. Woods Jr. go to Washington![]()
That is why the election of Rand Paul is so important. Schiff doesn't necessarily represent freedom very well. He does hold the same views, but he isn't concerned with many of them. Rand, on the other hand, has stated in his interview with Alex Jones that he wants to be involved with the government now so that when the dollar collapses, he will be the voice of reason. Schiff speaks all the time about how the dollar will fail, but not about what the U.S. will do afterwards.
He's like what, 70 years old? By the time 2012 rolls around, he'll be even older.
I think a younger person who shares his principles needs to step up to the plate.
There is already Schiff, Kokesh and others. If you are saying not run, its his decision, but I want him to run to have America hear his message one more time and know exactly what they didn't vote for the first time.
Then in the future, no matter what, America will have to live with the consequences of its choice in 2012.
I think he will run again in 2012, just to spread his message for one last time. He is so optimistic about his son, that I think he'll pass the torch after 2012. He's in very good health, and I just have a feeling...one can hope
The reasons why I think he'll run is twofold:
The Iraq and Afghan wars will still be going on and Afghan would have escalated tremendously.
The collapse of the dollar. He alone is the voice of the answer on Capitol Hill. He cannot pass up such an opportunity to turn this country around.
The collapse of the dollar. He alone is the voice of the answer on Capitol Hill. He cannot pass up such an opportunity to turn this country around.